Скалярное произведение векторов
Проверьте ортогональность данной системы векторов и дополните ее до ортогонального базиса пространства, если:
22.01.
= (1; –3; 2; –2),
= (6; 4; 2; 1);
22.02.
= (–3; 2; 4; –5),
= (1; 3; 3; 3);
22.03.
= (4; 5; –4; 2),
= (3; 2; 5; –1);
22.04.
= (–3; 2;–7; –2),
= (2; –4; –4; 7);
22.05.
= (11;–4;–3; 2),
= (2; 5;–6;–10);
22.06.
= (7;–4;15;–3),
= (–8; 1; 2; –10);
22.07.
= (–8; 4;–2; 8),
= (6; 5; –6; 2);
22.08.
= (–2; 4; 1; 8),
= (8; –8;24; 3);
22.09.
= (–3; 2; –1; 7),
= (–5; 3; 7; –2);
22.10.
= (2; –7; 4;–14),
= (–3; 6; 5; –2);
22.11.
= (1; 14; 6; –2),
= (–8; 2; –1; 7);
22.12.
= (–6; –2; 4; –2),
= (1; –3; 5; –10);
22.13.
= (3; 1; 6;–2),
= (2; –10; 1; 1);
22.14.
= (4; 1; –2; 3),
= (6; 2; 10; –2);
22.15.
= (2; 5; –3; 4),
= (4; 8; 12; –3);
22.16.
= (3; –2; –1; 1),
= (6; 4; 6; –4);
22.17
= (3; –4; –6; 2),
= (12; –1; 4;–8);
22.18.
= (2; –4; –1; 6),
= (8; –6; 10; –5);
22.19.
= (1; –2; 1; 2),
= (8; 6; –6; 5);
22.20.
= (–3; 5; –6; 1),
= (–1; 4; 5; –7);
22.21.
= (–1; 6; 2; –4),
= (8; –5; 10; –3);
22.22.
= (–1; 3; 7; –1),
= (6;–5; 1; –14);
22.23.
= (2; –3; –1; 4),
= (4;–10;10;–7);
22.24.
= (1; –8; –2; 4),
= (6; –1; 3; –2);
22.25.
= (4; 0; –4; 2),
= (–8; 3; –5; 6);
22.26.
= (1; 5; –2; 1),
= (10; 0; 4; –2);
22.27.
= (1; –2; 3; 2),
= (8; 3; –2; 2);
22.28.
= (5; 1; –5; 8),
= (4; –2; 2; –1);
22.29.
= (–1; 3; 2; –5),
= (–6; 5; –3; 3);
22.30.
= (3; 1; –7; –1),
= (1; 10; 2; –1);
22.31.
= (4; –1; 6; –2),
= (12; 8; –5; 5);
22.32.
= (4; –3; –5; –2),
= (2; 8; –2; –3);
22.33.
= (3; 1; 2; –2),
= (1; 3; 5; 8);
22.34.
= (1; 2; –4; 3),
= (–1; 5; 2; –1);
22.35.
= (1; 3; –1; 2; 1),
= (4; 1; 1;–3; 0);
22.36.
= (3; 2; –5; 0; 1),
= (–1; 1; 1; 3; 6).